展开 n/((nb-1-ib)i)

解答

展开

\frac{n}{( nb - 1 - ib ) i}

\frac{n}{nib - i - i ^{2} b}

求解步骤

\frac{n}{( nb - 1 - ib ) i}

乘开

(nb - 1 - ib) i : nib - i - i^{2} b

= \frac{n}{nib - i - i ^{2} b}

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