What are the solutions to the equation x^2-4x+9=0 ?

The solutions to the equation x^2-4x+9=0 are x=2+sqrt(5)i,x=2-sqrt(5)i

Find the zeros of x^2-4x+9=0

The zeros of x^2-4x+9=0 are x=2+sqrt(5)i,x=2-sqrt(5)i

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x^{2} - 4 x + 9 = 0

x = 2 + 5 i, x = 2 - 5 i

Solution steps

x^{2} - 4 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 9 : 25 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 5 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 5 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 5 i}{2 \cdot 1} : 2 + 5 i

x = \frac{- ( - 4 ) - 2 5 i}{2 \cdot 1} : 2 - 5 i

The solutions to the quadratic equation are:

x = 2 + 5 i, x = 2 - 5 i

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4 x^{2} - 3 x + 7 < 2 x^{2} + x + 7

\frac{- ( \frac{1}{36} ) ^{\frac{1}{8}}}{( 6 ) ^{- \frac{5}{4}}}

\frac{\frac{7}{2}}{\frac{7}{2} - 3}

x^{2} + 12 x = 7 x + 1

What are the solutions to the equation x^2-4x+9=0 ?
The solutions to the equation x^2-4x+9=0 are x=2+sqrt(5)i,x=2-sqrt(5)i
Find the zeros of x^2-4x+9=0
The zeros of x^2-4x+9=0 are x=2+sqrt(5)i,x=2-sqrt(5)i