faktorisieren 81a^4-49b^2

Lösung

faktorisieren

81 a^{4} - 49 b^{2}

(9 a^{2} + 7 b) (9 a^{2} - 7 b)

Schritte zur Lösung

81 a^{4} - 49 b^{2}

81 a^{4} = (9 a^{2})^{2}

49 b^{2} = (7 b)^{2}

= (9 a^{2})^{2} - (7 b)^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(9 a^{2})^{2} - (7 b)^{2} = (9 a^{2} + 7 b) (9 a^{2} - 7 b)

= (9 a^{2} + 7 b) (9 a^{2} - 7 b)

x^{2} - 10 x + 100 = 0

\frac{5}{X - 1} < 3

2 v > - 12

∣ x - 1 ∣ > - 2

\frac{m + 6}{6} \geq 2