16t^2-204t+100=0

解

16 t^{2} - 204 t + 100 = 0

t = \frac{51 + 2201}{8}, t = \frac{51 - 2201}{8}

十進法表記

t = 12.23935 \dots, t = 0.51064 \dots

解答ステップ

16 t^{2} - 204 t + 100 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 204 ) \pm ( - 204 ) ^{2} - 4 \cdot 16 \cdot 100}{2 \cdot 16}

(- 204)^{2} - 4 \cdot 16 \cdot 100 = 42201

t_{1, 2} = \frac{- ( - 204 ) \pm 4 2201}{2 \cdot 16}

解を分離する

t_{1} = \frac{- ( - 204 ) + 4 2201}{2 \cdot 16}, t_{2} = \frac{- ( - 204 ) - 4 2201}{2 \cdot 16}

t = \frac{- ( - 204 ) + 4 2201}{2 \cdot 16} : \frac{51 + 2201}{8}

t = \frac{- ( - 204 ) - 4 2201}{2 \cdot 16} : \frac{51 - 2201}{8}

二次equationの解:

t = \frac{51 + 2201}{8}, t = \frac{51 - 2201}{8}