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受欢迎的代数 >

solvefor a,λ^2-(a+3)λ+(3a+b)=0

解答

求解

a, λ^{2} - (a + 3) \cdot λ + (3 \cdot a + b) = 0

解答

a = \frac{- λ ^{2} - b + 3 λ}{- λ + 3}; λ \neq = 3

求解步骤

λ^{2} - (a + 3) λ + (3 a + b) = 0

λ^{2} - λ (a + 3) + 3 a + b = 0

将

λ^{2}

到右边

- λ (a + 3) + 3 a + b = - λ^{2}

将

b

到右边

- λ (a + 3) + 3 a = - λ^{2} - b

乘开

- λ (a + 3) : - λa - 3 λ

- λa - 3 λ + 3 a = - λ^{2} - b

将

3 λ

到右边

- λa + 3 a = - λ^{2} - b + 3 λ

分解

- λa + 3 a : a (- λ + 3)

a (- λ + 3) = - λ^{2} - b + 3 λ

两边除以

- λ + 3; λ \neq = 3

a = \frac{- λ ^{2} - b + 3 λ}{- λ + 3}; λ \neq = 3

作图

流行的例子

solvefor y,2x+y-1.3x-y=-9

so l v e f or y, 2 x + y - 1.3 x - y = - 9

2 n + 23 = - 19 - n

x/2+(2x+3)/3 =1

\frac{x}{2} + \frac{2 x + 3}{3} = 1

2 x - 10 = - 2

solvefor y,x=4y-8

so l v e f or y, x = 4 y - 8