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受欢迎的代数 >

solvefor k,f=2x^4+3x^3+2kx^2+3x+6

解答

求解

k, f = 2 x^{4} + 3 x^{3} + 2 k x^{2} + 3 x + 6

解答

k = \frac{f - 2 x ^{4} - 3 x ^{3} - 3 x - 6}{2 x ^{2}}; x \neq = 0

求解步骤

f = 2 x^{4} + 3 x^{3} + 2 k x^{2} + 3 x + 6

交换两边

2 x^{4} + 3 x^{3} + 2 k x^{2} + 3 x + 6 = f

将

2 x^{4}

到右边

3 x^{3} + 2 k x^{2} + 3 x + 6 = f - 2 x^{4}

将

3 x^{3}

到右边

2 k x^{2} + 3 x + 6 = f - 2 x^{4} - 3 x^{3}

将

3 x

到右边

2 k x^{2} + 6 = f - 2 x^{4} - 3 x^{3} - 3 x

将

6

到右边

2 k x^{2} = f - 2 x^{4} - 3 x^{3} - 3 x - 6

两边除以

2 x^{2}; x \neq = 0

k = \frac{f - 2 x ^{4} - 3 x ^{3} - 3 x - 6}{2 x ^{2}}; x \neq = 0

作图

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