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Frequently Asked Questions (FAQ)
What are the solutions to the equation 2b^2+3b=1 ?
- The solutions to the equation 2b^2+3b=1 are b=(-3+sqrt(17))/4 ,b=(-3-sqrt(17))/4
Find the zeros of 2b^2+3b=1
- The zeros of 2b^2+3b=1 are b=(-3+sqrt(17))/4 ,b=(-3-sqrt(17))/4