solvefor p,[(p∧ q)∨ ¬ (p∧ q)]=T

解

解く

p, [(p \land q) \lor \neg (p \land q)] = T

p = \frac{T}{\land \lor \neg \land q ^{2}}, p = - \frac{T}{\land \lor \neg \land q ^{2}}; q \neq = 0

解答ステップ

[(p \land q) \lor \neg (p \land q)] = T

簡素化

\land \lor \neg \land p^{2} q^{2} = T

以下で両辺を割る

\land \lor \neg \land q^{2}; q \neq = 0

\frac{\land \lor \neg \land p ^{2} q ^{2}}{\land \lor \neg \land q ^{2}} = \frac{T}{\land \lor \neg \land q ^{2}}; q \neq = 0

p^{2} = \frac{T}{\land \lor \neg \land q ^{2}}; q \neq = 0

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

p = \frac{T}{\land \lor \neg \land q ^{2}}, p = - \frac{T}{\land \lor \neg \land q ^{2}}; q \neq = 0