0=16.1t^2+57.4413

解

0 = 16.1 t^{2} + 57.4413

t = \frac{574413}{100 \frac{161}{10}} i, t = - \frac{574413}{100 \frac{161}{10}} i

解答ステップ

0 = 16.1 t^{2} + 57.4413

辺を交換する

16.1 t^{2} + 57.4413 = 0

57.4413

を右側に移動します

16.1 t^{2} = - 57.4413

以下で両辺を割る

16.1

t^{2} = - \frac{57.4413}{16.1}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

t = - \frac{57.4413}{16.1}, t = - - \frac{57.4413}{16.1}

- \frac{57.4413}{16.1} = \frac{574413}{100 \frac{161}{10}} i

- - \frac{57.4413}{16.1} = - \frac{574413}{100 \frac{161}{10}} i

t = \frac{574413}{100 \frac{161}{10}} i, t = - \frac{574413}{100 \frac{161}{10}} i