10x^2+20x=0

解

10 x^{2} + 20 x = 0

x = 0, x = - 2

解答ステップ

10 x^{2} + 20 x = 0

解くとthe二次式

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 10 \cdot 0}{2 \cdot 10}

2 0^{2} - 4 \cdot 10 \cdot 0 = 20

x_{1, 2} = \frac{- 20 \pm 20}{2 \cdot 10}

解を分離する

x_{1} = \frac{- 20 + 20}{2 \cdot 10}, x_{2} = \frac{- 20 - 20}{2 \cdot 10}

x = \frac{- 20 + 20}{2 \cdot 10} : 0

x = \frac{- 20 - 20}{2 \cdot 10} : - 2

二次equationの解:

x = 0, x = - 2