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受欢迎的代数 >

mx^2-2(m+1)x+2m=0

解答

m x^{2} - 2 (m + 1) x + 2 m = 0

解答

x = \frac{m + 1 + - m ^{2} + 2 m + 1}{m}, x = \frac{m + 1 - - m ^{2} + 2 m + 1}{m}; m \neq = 0

求解步骤

m x^{2} - 2 (m + 1) x + 2 m = 0

展开

m x^{2} - 2 (m + 1) x + 2 m : m x^{2} - 2 m x - 2 x + 2 m

m x^{2} - 2 m x - 2 x + 2 m = 0

改写成标准形式

a x^{2} + b x + c = 0

m x^{2} - (2 m + 2) x + 2 m = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 2 m - 2 ) \pm ( - 2 m - 2 ) ^{2} - 4 m \cdot 2 m}{2 m}

化简

(- 2 m - 2)^{2} - 4 m \cdot 2 m : 2 - m^{2} + 2 m + 1

x_{1, 2} = \frac{- ( - 2 m - 2 ) \pm 2 - m ^{2} + 2 m + 1}{2 m}; m \neq = 0

将解分隔开

x_{1} = \frac{- ( - 2 m - 2 ) + 2 - m ^{2} + 2 m + 1}{2 m}, x_{2} = \frac{- ( - 2 m - 2 ) - 2 - m ^{2} + 2 m + 1}{2 m}

x = \frac{- ( - 2 m - 2 ) + 2 - m ^{2} + 2 m + 1}{2 m} : \frac{m + 1 + - m ^{2} + 2 m + 1}{m}

x = \frac{- ( - 2 m - 2 ) - 2 - m ^{2} + 2 m + 1}{2 m} : \frac{m + 1 - - m ^{2} + 2 m + 1}{m}

二次方程组的解是:

x = \frac{m + 1 + - m ^{2} + 2 m + 1}{m}, x = \frac{m + 1 - - m ^{2} + 2 m + 1}{m}; m \neq = 0

作图

流行的例子

(2 x + 5)^{2} = 16

x^2+6x+20=-1/2 x^2-4x+196

x^{2} + 6 x + 20 = - \frac{1}{2} x^{2} - 4 x + 196

- 4 x^{2} - 4 = 0

25 x^{2} + 5 = 0

x (x + 12) = 12