24x^2+128x-512=0

解

24 x^{2} + 128 x - 512 = 0

x = \frac{8}{3}, x = - 8

十進法表記

x = 2.66666 \dots, x = - 8

解答ステップ

24 x^{2} + 128 x - 512 = 0

解くとthe二次式

x_{1, 2} = \frac{- 128 \pm 12 8 ^{2} - 4 \cdot 24 ( - 512 )}{2 \cdot 24}

12 8^{2} - 4 \cdot 24 (- 512) = 256

x_{1, 2} = \frac{- 128 \pm 256}{2 \cdot 24}

解を分離する

x_{1} = \frac{- 128 + 256}{2 \cdot 24}, x_{2} = \frac{- 128 - 256}{2 \cdot 24}

x = \frac{- 128 + 256}{2 \cdot 24} : \frac{8}{3}

x = \frac{- 128 - 256}{2 \cdot 24} : - 8

二次equationの解:

x = \frac{8}{3}, x = - 8