(x-1)(x-2)(x-6)<= 0

Lösung

(x - 1) (x - 2) (x - 6) \leq 0

x \leq 1 or 2 \leq x \leq 6

Intervall-Notation

(- \infty, 1] \cup [2, 6]

Schritte zur Lösung

(x - 1) (x - 2) (x - 6) \leq 0

Identifiziere die Intervalle

x \leq 1 or 2 \leq x \leq 6

6 x + 11 = - (6 x + 5)

x^{2} + 5 x - 8 = 4 x + 4

2 x^{2} + x \geq 28

\frac{1}{x} + \frac{1}{3} < \frac{1}{5}

6 x^{2} + x - 2 = 0