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受欢迎的代数 >

4.905t^2-42.5t+120=0

解答

4.905 t^{2} - 42.5 t + 120 = 0

解答

t = \frac{4250}{981} + i \frac{2354400000 - 4250 0 ^{2}}{9810}, t = \frac{4250}{981} - i \frac{2354400000 - 4250 0 ^{2}}{9810}

求解步骤

4.905 t^{2} - 42.5 t + 120 = 0

在两边乘以

1000

4905 t^{2} - 42500 t + 120000 = 0

使用求根公式求解

t_{1, 2} = \frac{- ( - 42500 ) \pm ( - 42500 ) ^{2} - 4 \cdot 4905 \cdot 120000}{2 \cdot 4905}

化简

(- 42500)^{2} - 4 \cdot 4905 \cdot 120000 : i - 4250 0^{2} + 2354400000

t_{1, 2} = \frac{- ( - 42500 ) \pm i - 4250 0 ^{2} + 2354400000}{2 \cdot 4905}

将解分隔开

t_{1} = \frac{- ( - 42500 ) + i - 4250 0 ^{2} + 2354400000}{2 \cdot 4905}, t_{2} = \frac{- ( - 42500 ) - i - 4250 0 ^{2} + 2354400000}{2 \cdot 4905}

t = \frac{- ( - 42500 ) + i - 4250 0 ^{2} + 2354400000}{2 \cdot 4905} : \frac{4250}{981} + i \frac{2354400000 - 4250 0 ^{2}}{9810}

t = \frac{- ( - 42500 ) - i - 4250 0 ^{2} + 2354400000}{2 \cdot 4905} : \frac{4250}{981} - i \frac{2354400000 - 4250 0 ^{2}}{9810}

二次方程组的解是:

t = \frac{4250}{981} + i \frac{2354400000 - 4250 0 ^{2}}{9810}, t = \frac{4250}{981} - i \frac{2354400000 - 4250 0 ^{2}}{9810}

作图

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