((sqrt(5)-5)/2)^2+y^2=5

解

(\frac{5 - 5}{2})^{2} + y^{2} = 5

y = \frac{- 5 + 5 5}{2}, y = - \frac{- 5 + 5 5}{2}

十進法表記

y = 1.75788 \dots, y = - 1.75788 \dots

解答ステップ

(\frac{5 - 5}{2})^{2} + y^{2} = 5

(\frac{5 - 5}{2})^{2}

を右側に移動します

y^{2} = 5 - \frac{( 5 - 5 ) ^{2}}{4}

\frac{( 5 - 5 ) ^{2}}{4} = \frac{5 ( 3 - 5 )}{2}

y^{2} = 5 - \frac{5 ( 3 - 5 )}{2}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

y = 5 - \frac{5 ( 3 - 5 )}{2}, y = - 5 - \frac{5 ( 3 - 5 )}{2}

5 - \frac{5 ( 3 - 5 )}{2} = \frac{- 5 + 5 5}{2}

- 5 - \frac{5 ( 3 - 5 )}{2} = - \frac{- 5 + 5 5}{2}

y = \frac{- 5 + 5 5}{2}, y = - \frac{- 5 + 5 5}{2}