t^2-6t+5=0

解

t^{2} - 6 t + 5 = 0

t = 5, t = 1

解答ステップ

t^{2} - 6 t + 5 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

t_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

解を分離する

t_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

t = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

t = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

二次equationの解:

t = 5, t = 1