3y^2+24y+36=0

解

3 y^{2} + 24 y + 36 = 0

y = - 2, y = - 6

解答ステップ

3 y^{2} + 24 y + 36 = 0

解くとthe二次式

y_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 3 \cdot 36}{2 \cdot 3}

2 4^{2} - 4 \cdot 3 \cdot 36 = 12

y_{1, 2} = \frac{- 24 \pm 12}{2 \cdot 3}

解を分離する

y_{1} = \frac{- 24 + 12}{2 \cdot 3}, y_{2} = \frac{- 24 - 12}{2 \cdot 3}

y = \frac{- 24 + 12}{2 \cdot 3} : - 2

y = \frac{- 24 - 12}{2 \cdot 3} : - 6

二次equationの解:

y = - 2, y = - 6