X^2-7X+12=0

解答

X^{2} - 7 X + 12 = 0

X = 4, X = 3

求解步骤

X^{2} - 7 X + 12 = 0

使用求根公式求解

X_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 12 = 1

X_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 1}

将解分隔开

X_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 1}, X_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 1}

X = \frac{- ( - 7 ) + 1}{2 \cdot 1} : 4

X = \frac{- ( - 7 ) - 1}{2 \cdot 1} : 3

二次方程组的解是:

X = 4, X = 3

- 9 n^{2} + 2 n + 21 = - 5 n^{2}

f a c t or 4 x^{2} + 6 x = 0

- 8 + x^{2} = 0

co m pl e t es q u a re x^{2} + 4 x - 8 = 0

f a c t or x^{2} + 5 x - 24 = 0