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受欢迎的代数 >

(3x+2)(5x+1)=ax^2+bx+2

解答

(3 x + 2) (5 x + 1) = a x^{2} + b x + 2

解答

x = 0, x = \frac{b - 13}{15 - a}; a \neq = 15

求解步骤

(3 x + 2) (5 x + 1) = a x^{2} + b x + 2

展开

(3 x + 2) (5 x + 1) : 15 x^{2} + 13 x + 2

15 x^{2} + 13 x + 2 = a x^{2} + b x + 2

将

2

para o lado esquerdo

15 x^{2} + 13 x = a x^{2} + b x

将

b x

para o lado esquerdo

15 x^{2} + 13 x - b x = a x^{2}

将

a x^{2}

para o lado esquerdo

15 x^{2} + 13 x - b x - a x^{2} = 0

改写成标准形式

a x^{2} + b x + c = 0

(15 - a) x^{2} + (13 - b) x = 0

因式分解

(15 - a) x^{2} + (13 - b) x : x (15 x - a x - b + 13)

x (15 x - a x - b + 13) = 0

使用零因数法则： If

ab = 0

then

a = 0

or

b = 0

x = 0 or 15 x - a x - b + 13 = 0

解

15 x - a x - b + 13 = 0 : x = \frac{b - 13}{15 - a}; a \neq = 15

二次方程组的解是:

x = 0, x = \frac{b - 13}{15 - a}; a \neq = 15

作图

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