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受欢迎的代数 >

solvefor m,Lm^2+Rm+1/c =0

解答

求解

m, L m^{2} + R m + \frac{1}{c} = 0

解答

m = \frac{- c R + c ^{2} R ^{2} - 4 L c}{2 L c}, m = \frac{- c R - c ^{2} R ^{2} - 4 L c}{2 L c}; L c \neq = 0

求解步骤

L m^{2} + R m + \frac{1}{c} = 0

在两边乘以

c

L c m^{2} + c R m + 1 = 0; c \neq = 0

使用求根公式求解

m_{1, 2} = \frac{- c R \pm ( c R ) ^{2} - 4 L c \cdot 1}{2 L c}

化简

(c R)^{2} - 4 L c \cdot 1 : c^{2} R^{2} - 4 L c

m_{1, 2} = \frac{- c R \pm c ^{2} R ^{2} - 4 L c}{2 L c}; L c \neq = 0

将解分隔开

m_{1} = \frac{- c R + c ^{2} R ^{2} - 4 L c}{2 L c}, m_{2} = \frac{- c R - c ^{2} R ^{2} - 4 L c}{2 L c}

m = \frac{- c R + c ^{2} R ^{2} - 4 L c}{2 L c}; L c \neq = 0

m = \frac{- c R - c ^{2} R ^{2} - 4 L c}{2 L c}; L c \neq = 0

二次方程组的解是:

m = \frac{- c R + c ^{2} R ^{2} - 4 L c}{2 L c}, m = \frac{- c R - c ^{2} R ^{2} - 4 L c}{2 L c}; L c \neq = 0

作图

流行的例子

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