0=x^2-10x+24

解答

0 = x^{2} - 10 x + 24

x = 6, x = 4

求解步骤

0 = x^{2} - 10 x + 24

交换两边

x^{2} - 10 x + 24 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 24 = 2

x_{1, 2} = \frac{- ( - 10 ) \pm 2}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 10 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2}{2 \cdot 1} : 6

x = \frac{- ( - 10 ) - 2}{2 \cdot 1} : 4

二次方程组的解是:

x = 6, x = 4

5 (x + 4)^{2} = 2 (x + 1)^{2} - 27

x^{2} - 100 x + 2500 = 1152 π^{2} x - 56700 π^{2}

x^{2} - x - 21 = 0

so l v e f or x, 16 x^{2} + 25 y^{2} + 400 = 0

so l v e f or x, (f \circ g) f = x^{2}