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人気のある代数 >

(k-2)x^2+3x+k=0

解

(k - 2) x^{2} + 3 x + k = 0

解

x = \frac{- 3 + 9 - 4 k ( k - 2 )}{2 ( k - 2 )}, x = \frac{- 3 - 9 - 4 k ( k - 2 )}{2 ( k - 2 )}; k \neq = 2

解答ステップ

(k - 2) x^{2} + 3 x + k = 0

解くとthe二次式

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( k - 2 ) k}{2 ( k - 2 )}

簡素化

3^{2} - 4 (k - 2) k : 9 - 4 k (k - 2)

x_{1, 2} = \frac{- 3 \pm 9 - 4 k ( k - 2 )}{2 ( k - 2 )}; k \neq = 2

解を分離する

x_{1} = \frac{- 3 + 9 - 4 k ( k - 2 )}{2 ( k - 2 )}, x_{2} = \frac{- 3 - 9 - 4 k ( k - 2 )}{2 ( k - 2 )}

x = \frac{- 3 + 9 - 4 k ( k - 2 )}{2 ( k - 2 )}; k \neq = 2

x = \frac{- 3 - 9 - 4 k ( k - 2 )}{2 ( k - 2 )}; k \neq = 2

二次equationの解:

x = \frac{- 3 + 9 - 4 k ( k - 2 )}{2 ( k - 2 )}, x = \frac{- 3 - 9 - 4 k ( k - 2 )}{2 ( k - 2 )}; k \neq = 2

グラフ

人気の例

5 x^{2} + 6 = 0

solvefor x,(x+y)^2=0

so l v e f or x, (x + y)^{2} = 0

(x-1)^2+4(x-1)(x-3)-2(2x-3)^2=0

(x - 1)^{2} + 4 (x - 1) (x - 3) - 2 (2 x - 3)^{2} = 0

z^{2} = 2

(x + 1)^{2} = - 5