quadraticformula x^2+12x+35=0

解

x^{2} + 12 x + 35 = 0

x = - 5, x = - 7

解答ステップ

x^{2} + 12 x + 35 = 0

解くとthe二次式

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 35 = 2

x_{1, 2} = \frac{- 12 \pm 2}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 12 + 2}{2 \cdot 1}, x_{2} = \frac{- 12 - 2}{2 \cdot 1}

x = \frac{- 12 + 2}{2 \cdot 1} : - 5

x = \frac{- 12 - 2}{2 \cdot 1} : - 7

二次equationの解:

x = - 5, x = - 7