n^2-4n+4=0

解

n^{2} - 4 n + 4 = 0

n = 2

解答ステップ

n^{2} - 4 n + 4 = 0

解くとthe二次式

n_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

n_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

n = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

n = 2

二次equationの解:

n = 2