a^2+2a+3=0

解答

a^{2} + 2 a + 3 = 0

a = - 1 + 2 i, a = - 1 - 2 i

求解步骤

a^{2} + 2 a + 3 = 0

使用求根公式求解

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

化简

2^{2} - 4 \cdot 1 \cdot 3 : 22 i

a_{1, 2} = \frac{- 2 \pm 2 2 i}{2 \cdot 1}

将解分隔开

a_{1} = \frac{- 2 + 2 2 i}{2 \cdot 1}, a_{2} = \frac{- 2 - 2 2 i}{2 \cdot 1}

a = \frac{- 2 + 2 2 i}{2 \cdot 1} : - 1 + 2 i

a = \frac{- 2 - 2 2 i}{2 \cdot 1} : - 1 - 2 i

二次方程组的解是:

a = - 1 + 2 i, a = - 1 - 2 i

x^{2} + (n + 3) x + n + 2 = 0

so l v e f or f, f = f (x + 2) - 3

x^{2} + 9 = 8 x

so l v e f or x, x^{2} y + y^{2} x = 6

so l v e f or p, x^{2} p^{2} + x y p - 6 y^{2} = 0