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受欢迎的代数 >

r^2+2r+32=0

解答

r^{2} + 2 r + 32 = 0

解答

r = - 1 + 31 i, r = - 1 - 31 i

求解步骤

r^{2} + 2 r + 32 = 0

使用求根公式求解

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

化简

2^{2} - 4 \cdot 1 \cdot 32 : 231 i

r_{1, 2} = \frac{- 2 \pm 2 31 i}{2 \cdot 1}

将解分隔开

r_{1} = \frac{- 2 + 2 31 i}{2 \cdot 1}, r_{2} = \frac{- 2 - 2 31 i}{2 \cdot 1}

r = \frac{- 2 + 2 31 i}{2 \cdot 1} : - 1 + 31 i

r = \frac{- 2 - 2 31 i}{2 \cdot 1} : - 1 - 31 i

二次方程组的解是:

r = - 1 + 31 i, r = - 1 - 31 i

作图

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