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受欢迎的代数 >

solvefor b,A= 1/2 h(b^1+b^2)

解答

求解

b, A = \frac{1}{2} h (b^{1} + b^{2})

解答

b = \frac{- h + h ^{2} + 8 A h}{2 h}, b = \frac{- h - h ^{2} + 8 A h}{2 h}; h \neq = 0

求解步骤

A = \frac{1}{2} h (b^{1} + b^{2})

在两边乘以

2

2 A = h (b + b^{2})

展开

h (b + b^{2}) : bh + b^{2} h

2 A = bh + b^{2} h

交换两边

bh + b^{2} h = 2 A

将

2 A

para o lado esquerdo

bh + b^{2} h - 2 A = 0

改写成标准形式

a x^{2} + b x + c = 0

h b^{2} + hb - 2 A = 0

使用求根公式求解

b_{1, 2} = \frac{- h \pm h ^{2} - 4 h ( - 2 A )}{2 h}

化简

h^{2} - 4 h (- 2 A) : h^{2} + 8 A h

b_{1, 2} = \frac{- h \pm h ^{2} + 8 A h}{2 h}; h \neq = 0

将解分隔开

b_{1} = \frac{- h + h ^{2} + 8 A h}{2 h}, b_{2} = \frac{- h - h ^{2} + 8 A h}{2 h}

b = \frac{- h + h ^{2} + 8 A h}{2 h}; h \neq = 0

b = \frac{- h - h ^{2} + 8 A h}{2 h}; h \neq = 0

二次方程组的解是:

b = \frac{- h + h ^{2} + 8 A h}{2 h}, b = \frac{- h - h ^{2} + 8 A h}{2 h}; h \neq = 0

作图

流行的例子

2 x^{2} - 8 x - 8 = 0

2x^2-(a+6)x+3a=0

2 x^{2} - (a + 6) x + 3 a = 0

9 x^{2} - 7 x - 9 = 0

completesquare x^2-x+7

co m pl e t es q u a re x^{2} - x + 7

completesquare x^2-x+9

co m pl e t es q u a re x^{2} - x + 9