solvefor x,2x^2+5x-3=0

解

x, 2 x^{2} + 5 x - 3 = 0

x = \frac{1}{2}, x = - 3

十進法表記

x = 0.5, x = - 3

解答ステップ

2 x^{2} + 5 x - 3 = 0

解くとthe二次式

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 3) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 5 + 7}{2 \cdot 2}, x_{2} = \frac{- 5 - 7}{2 \cdot 2}

x = \frac{- 5 + 7}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 5 - 7}{2 \cdot 2} : - 3

二次equationの解:

x = \frac{1}{2}, x = - 3