solvefor c,4c^2θt=(θ^2-t^2)^2

Lösung

löse nach

c, 4 c^{2} θt = (θ^{2} - t^{2})^{2}

c = \frac{θ ^{2} - t ^{2}}{2 θt}, c = - \frac{θ ^{2} - t ^{2}}{2 θt}; θ \neq = 0

Schritte zur Lösung

4 c^{2} θt = (θ^{2} - t^{2})^{2}

Teile beide Seiten durch

4 θt; θ \neq = 0

c^{2} = \frac{( θ ^{2} - t ^{2} ) ^{2}}{4 θt}; θ \neq = 0

Für

x^{2} = f (a)

sind die Lösungen

x = f (a), - f (a)

c = \frac{( θ ^{2} - t ^{2} ) ^{2}}{4 θt}, c = - \frac{( θ ^{2} - t ^{2} ) ^{2}}{4 θt}; θ \neq = 0

Vereinfache

\frac{( θ ^{2} - t ^{2} ) ^{2}}{4 θt} : \frac{θ ^{2} - t ^{2}}{2 θt}

Vereinfache

- \frac{( θ ^{2} - t ^{2} ) ^{2}}{4 θt} : - \frac{θ ^{2} - t ^{2}}{2 θt}

c = \frac{θ ^{2} - t ^{2}}{2 θt}, c = - \frac{θ ^{2} - t ^{2}}{2 θt}; θ \neq = 0

y^{2} + 5 y = 0

so l v e f or a, a (a - y) = b (y - b) - 2 ab

x^{2} - 2 x = 10

y^{2} + y + 1 = 0

2 x^{2} - 4 x + 8 = 0