4x^2-40x-96=0

解

4 x^{2} - 40 x - 96 = 0

x = 12, x = - 2

解答ステップ

4 x^{2} - 40 x - 96 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 4 ( - 96 )}{2 \cdot 4}

(- 40)^{2} - 4 \cdot 4 (- 96) = 56

x_{1, 2} = \frac{- ( - 40 ) \pm 56}{2 \cdot 4}

解を分離する

x_{1} = \frac{- ( - 40 ) + 56}{2 \cdot 4}, x_{2} = \frac{- ( - 40 ) - 56}{2 \cdot 4}

x = \frac{- ( - 40 ) + 56}{2 \cdot 4} : 12

x = \frac{- ( - 40 ) - 56}{2 \cdot 4} : - 2

二次equationの解:

x = 12, x = - 2