What is (2pir*1/(pir^2))*2(pir^2) ?

The solution to (2pir*1/(pir^2))*2(pir^2) is 4pir

simplify (2pir*1/(pir^2))*2(pir^2)

simplify

(2 π r \cdot \frac{1}{π r ^{2}}) \cdot 2 (π r^{2})

4 π r

Solution steps

(2 π r \frac{1}{π r ^{2}}) \cdot 2 (π r^{2})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2 = 2^{1 + 1}

= π r \frac{1}{π r ^{2}} \cdot 2^{1 + 1} π r^{2}

Add the numbers:

1 + 1 = 2

= π r \frac{1}{π r ^{2}} \cdot 2^{2} π r^{2}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

r r^{2} = r^{1 + 2}

= π \frac{1}{π r ^{2}} \cdot 2^{2} π r^{1 + 2}

Add the numbers:

1 + 2 = 3

= π \frac{1}{π r ^{2}} \cdot 2^{2} π r^{3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ππ = π^{1 + 1}

= \frac{1}{π r ^{2}} \cdot 2^{2} π^{1 + 1} r^{3}

Add the numbers:

1 + 1 = 2

= \frac{1}{π r ^{2}} \cdot 2^{2} π^{2} r^{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2 ^{2} π ^{2} r ^{3}}{π r ^{2}}

Multiply:

1 \cdot 2^{2} = 2^{2}

= \frac{2 ^{2} π ^{2} r ^{3}}{π r ^{2}}

Cancel the common factor:

π

= \frac{2 ^{2} π r ^{3}}{r ^{2}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{r ^{3}}{r ^{2}} = r^{3 - 2}

= 2^{2} π r^{3 - 2}

Subtract the numbers:

3 - 2 = 1

= 2^{2} π r

2^{2} = 4

= 4 π r

s im pl i f y e^{- a t} \cdot cos (4 \cdot t)

s im pl i f y e^{- 3.5 x^{2}}

s im pl i f y 4 x^{4} y^{3} (17 x^{17} y^{7} z^{3})

s im pl i f y π (\frac{( 1.5 \cdot 1 0 ^{- 3} )}{2})^{2} \cdot (6 \cdot 1 0^{28}) (86400) (1 \cdot 1 0^{- 4})

s im pl i f y \frac{2}{3 x}

What is (2pir*1/(pir^2))*2(pir^2) ?
The solution to (2pir*1/(pir^2))*2(pir^2) is 4pir