What is (a^2bc^2)(b^2c^3)(9a) ?

The solution to (a^2bc^2)(b^2c^3)(9a) is 9a^3b^3c^5

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simplify (a^2bc^2)(b^2c^3)(9a)

simplify

(a^{2} b c^{2}) (b^{2} c^{3}) (9 a)

9 a^{3} b^{3} c^{5}

Solution steps

(a^{2} b c^{2}) (b^{2} c^{3}) (9 a)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

a^{2} a = a^{2 + 1}

= b c^{2} b^{2} c^{3} \cdot 9 a^{2 + 1}

Add the numbers:

2 + 1 = 3

= b c^{2} b^{2} c^{3} \cdot 9 a^{3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

b b^{2} = b^{1 + 2}

= c^{2} b^{1 + 2} c^{3} \cdot 9 a^{3}

Add the numbers:

1 + 2 = 3

= c^{2} b^{3} c^{3} \cdot 9 a^{3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

c^{2} c^{3} = c^{2 + 3}

= b^{3} c^{2 + 3} \cdot 9 a^{3}

Add the numbers:

2 + 3 = 5

= b^{3} c^{5} \cdot 9 a^{3}

- e^{- x} (x e^{- x})

8.56 \cdot 314.15 \cdot 1 0^{- 4}

\frac{3 \cdot 1 0 ^{8}}{4 \cdot 11 \cdot 1 0 ^{- 3}} \cdot 1 0^{- 9}

\frac{3}{2 z}

What is (a^2bc^2)(b^2c^3)(9a) ?
The solution to (a^2bc^2)(b^2c^3)(9a) is 9a^3b^3c^5