What is \sqrt[3]{18^2} ?

The solution to \sqrt[3]{18^2} is 3\sqrt[3]{12}

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simplify \sqrt[3]{18^2}

simplify

Decimal Notation

6.86828 \dots

Solution steps

1 8^{2} = 324

Prime factorization of

324 : 2^{2} \cdot 3^{4}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

2^{2} \cdot 3^{4} = 2^{2} \cdot 3^{3} \cdot 3

Apply radical rule:

2^{2} = 4

Multiply the numbers:

4 \cdot 3 = 12

(- 1)^{- \frac{3}{2}}

(e^{2 x^{3}})^{- 6 x^{2} + 3}

- 1^{n} \cdot 2^{n}

((2^{3})^{- 2})^{0.5} \cdot ((0.5)^{0.75})^{- 4}

e^{- 0.7692}