What is expand 5(2xe^x+e^xx^2) ?

The solution to expand 5(2xe^x+e^xx^2) is 10e^xx+5e^xx^2

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expand 5(2xe^x+e^xx^2)

expand

5 (2 x e^{x} + e^{x} x^{2})

10 e^{x} x + 5 e^{x} x^{2}

Solution steps

5 (2 x e^{x} + e^{x} x^{2})

= 5 (2 e^{x} x + e^{x} x^{2})

Apply the distributive law:

a (b + c) = ab + a c

a = 5, b = 2 x e^{x}, c = e^{x} x^{2}

= 5 \cdot 2 x e^{x} + 5 e^{x} x^{2}

= 5 \cdot 2 e^{x} x + 5 e^{x} x^{2}

Multiply the numbers:

5 \cdot 2 = 10

= 10 e^{x} x + 5 e^{x} x^{2}

(tan (x) - sin (x) sin (y)) d x + cos (x) cos (y) d y

\frac{7 s + 1}{( s + 1 ) ( s - 1 )}

a (2 x, x) b (- 3, - 1) c (8, - 2)

cos ((3 - n) π)

y (\frac{x ^{2}}{y ^{2}} - 2)

What is expand 5(2xe^x+e^xx^2) ?
The solution to expand 5(2xe^x+e^xx^2) is 10e^xx+5e^xx^2