What is expand 9(x+Δx)^2-9(x+Δx) ?

The solution to expand 9(x+Δx)^2-9(x+Δx) is 9x^2+18Δx^2+9Δ^2x^2-9x-9Δx

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expand 9(x+Δx)^2-9(x+Δx)

expand

9 (x + Δ x)^{2} - 9 (x + Δ x)

9 x^{2} + 18Δ x^{2} + 9 Δ^{2} x^{2} - 9 x - 9Δ x

Solution steps

9 (x + Δ x)^{2} - 9 (x + Δ x)

Expand

- 9 (x + Δ x) : - 9 x - 9Δ x

= 9 (x + Δ x)^{2} - 9 x - 9Δ x

Simplify

9 (x + Δ x)^{2} - 9 x - 9Δ x : 9 x^{2} + 18Δ x^{2} + 9 Δ^{2} x^{2} - 9 x - 9Δ x

= 9 x^{2} + 18Δ x^{2} + 9 Δ^{2} x^{2} - 9 x - 9Δ x

5 (25 - x^{2} + 5) 25 - x^{2}

\frac{1}{( 3 - x ) ^{3}}

\frac{- 3 x ^{2} - 3 x + 27}{( x + 2 ) ( 2 x ^{2} + 3 x - 9 )}

N e^{3 x} \cdot 3 + M e^{x} + G (e^{x} + e^{x} x)

(1 - cot (x)) (1 + cos (x))

What is expand 9(x+Δx)^2-9(x+Δx) ?
The solution to expand 9(x+Δx)^2-9(x+Δx) is 9x^2+18Δx^2+9Δ^2x^2-9x-9Δx