What is expand ((2^t))/((t+1)(t-1)) ?

The solution to expand ((2^t))/((t+1)(t-1)) is (2^t)/(t^2-1)

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expand ((2^t))/((t+1)(t-1))

expand

\frac{( 2 ^{t} )}{( t + 1 ) ( t - 1 )}

\frac{2 ^{t}}{t ^{2} - 1}

Solution steps

\frac{2 ^{t}}{( t + 1 ) ( t - 1 )}

Expand

(t + 1) (t - 1) : t^{2} - 1

= \frac{2 ^{t}}{t ^{2} - 1}

\frac{0.8 ( s - 1 )}{( s + 1 ) ( 0.3 s + 1 )}

cos^{2} (A) (1 + 2 tan (A)) + sin^{2} (A)

x^{\frac{1}{4}} (3 x - 3)

\frac{( \frac{7}{9} ( 3 x sin ( 3 x ) + cos ( 3 x ) ) + C )}{x}

\frac{( k ) ( 2 p + 1 ) ^{2}}{p ( 0.5 p + 1 ) ^{2} ( p ^{2} + p + 1 )}

What is expand ((2^t))/((t+1)(t-1)) ?
The solution to expand ((2^t))/((t+1)(t-1)) is (2^t)/(t^2-1)