What is expand 4/((4n-3)(4n+1)) ?

The solution to expand 4/((4n-3)(4n+1)) is 4/(16n^2-8n-3)

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expand 4/((4n-3)(4n+1))

expand

\frac{4}{( 4 n - 3 ) ( 4 n + 1 )}

\frac{4}{16 n ^{2} - 8 n - 3}

Solution steps

\frac{4}{( 4 n - 3 ) ( 4 n + 1 )}

Expand

(4 n - 3) (4 n + 1) : 16 n^{2} - 8 n - 3

= \frac{4}{16 n ^{2} - 8 n - 3}

(1 - 3 x - 2) (x + 3 + 2)

x (2 x - 2 x)

3 + x (13 + e^{14 x - 7})

\frac{2 x}{( x ^{2} - 3 ) ^{2}}

\frac{( 2 ^{t} )}{( t + 1 ) ( t - 1 )}

What is expand 4/((4n-3)(4n+1)) ?
The solution to expand 4/((4n-3)(4n+1)) is 4/(16n^2-8n-3)