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受欢迎的代数 >

化简 (2+7i)^6

解答

化简

(2 + 7 i)^{6}

解答

14715 + 148148 i

求解步骤

(2 + 7 i)^{6}

使用二项式定理:

(a + b)^{n} = i = 0 \sum n (i n) a^{(n - i)} b^{i}

a = 2, b = 7 i

= i = 0 \sum 6 (i 6) \cdot 2^{(6 - i)} (7 i)^{i}

展开求和

= \frac{6 !}{0 ! ( 6 - 0 ) !} \cdot 2^{6} (7 i)^{0} + \frac{6 !}{1 ! ( 6 - 1 ) !} \cdot 2^{5} (7 i)^{1} + \frac{6 !}{2 ! ( 6 - 2 ) !} \cdot 2^{4} (7 i)^{2} + \frac{6 !}{3 ! ( 6 - 3 ) !} \cdot 2^{3} (7 i)^{3} + \frac{6 !}{4 ! ( 6 - 4 ) !} \cdot 2^{2} (7 i)^{4} + \frac{6 !}{5 ! ( 6 - 5 ) !} \cdot 2^{1} (7 i)^{5} + \frac{6 !}{6 ! ( 6 - 6 ) !} \cdot 2^{0} (7 i)^{6}

化简

\frac{6 !}{0 ! ( 6 - 0 ) !} \cdot 2^{6} (7 i)^{0} : 64

化简

\frac{6 !}{1 ! ( 6 - 1 ) !} \cdot 2^{5} (7 i)^{1} : 1344 i

化简

\frac{6 !}{2 ! ( 6 - 2 ) !} \cdot 2^{4} (7 i)^{2} : 11760 i^{2}

化简

\frac{6 !}{3 ! ( 6 - 3 ) !} \cdot 2^{3} (7 i)^{3} : 54880 i^{3}

化简

\frac{6 !}{4 ! ( 6 - 4 ) !} \cdot 2^{2} (7 i)^{4} : 144060 i^{4}

化简

\frac{6 !}{5 ! ( 6 - 5 ) !} \cdot 2^{1} (7 i)^{5} : 201684 i^{5}

化简

\frac{6 !}{6 ! ( 6 - 6 ) !} \cdot 2^{0} (7 i)^{6} : 117649 i^{6}

= 64 + 1344 i + 11760 i^{2} + 54880 i^{3} + 144060 i^{4} + 201684 i^{5} + 117649 i^{6}

化简

64 + 1344 i + 11760 i^{2} + 54880 i^{3} + 144060 i^{4} + 201684 i^{5} + 117649 i^{6} : 148148 i + 14715

= 148148 i + 14715

Rewrite in standard complex form:

14715 + 148148 i

= 14715 + 148148 i

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