What is expand (-2e^{1/x}+x(2e^{1/x}-2))/(3x) ?

The solution to expand (-2e^{1/x}+x(2e^{1/x}-2))/(3x) is -(2e^{1/x}}{3x}+\frac{2e^{1/x})/3-2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (-2e^{1/x}+x(2e^{1/x}-2))/(3x)

expand

\frac{- 2 e ^{\frac{1}{x}} + x ( 2 e ^{\frac{1}{x}} - 2 )}{3 x}

- \frac{2 e ^{\frac{1}{x}}}{3 x} + \frac{2 e ^{\frac{1}{x}}}{3} - \frac{2}{3}

Solution steps

\frac{- 2 e ^{\frac{1}{x}} + x ( 2 e ^{\frac{1}{x}} - 2 )}{3 x}

Expand

- 2 e^{\frac{1}{x}} + x (2 e^{\frac{1}{x}} - 2) : - 2 e^{\frac{1}{x}} + 2 e^{\frac{1}{x}} x - 2 x

= \frac{- 2 e ^{\frac{1}{x}} + 2 e ^{\frac{1}{x}} x - 2 x}{3 x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 2 e ^{\frac{1}{x}} + 2 e ^{\frac{1}{x}} x - 2 x}{3 x} = - \frac{2 e ^{\frac{1}{x}}}{3 x} + \frac{2 e ^{\frac{1}{x}} x}{3 x} - \frac{2 x}{3 x}

= - \frac{2 e ^{\frac{1}{x}}}{3 x} + \frac{2 e ^{\frac{1}{x}} x}{3 x} - \frac{2 x}{3 x}

Cancel

\frac{2 e ^{\frac{1}{x}} x}{3 x} : \frac{2 e ^{\frac{1}{x}}}{3}

= - \frac{2 e ^{\frac{1}{x}}}{3 x} + \frac{2 e ^{\frac{1}{x}}}{3} - \frac{2 x}{3 x}

Cancel

\frac{2 x}{3 x} : \frac{2}{3}

= - \frac{2 e ^{\frac{1}{x}}}{3 x} + \frac{2 e ^{\frac{1}{x}}}{3} - \frac{2}{3}

δ (x - y y_{2}), y_{2}

, 4 ((\frac{1}{2}) + i (\frac{3}{2}))

\frac{1}{4} (1.2 - 1) + \frac{1}{2}

- 5 (- 4 - 2)

What is expand (-2e^{1/x}+x(2e^{1/x}-2))/(3x) ?
The solution to expand (-2e^{1/x}+x(2e^{1/x}-2))/(3x) is -(2e^{1/x}}{3x}+\frac{2e^{1/x})/3-2/3