What is expand (2yy'(x)=20x^3-2x) 1/2 ?

The solution to expand (2yy'(x)=20x^3-2x) 1/2 is yy'(x)=20x^3-x

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expand (2yy'(x)=20x^3-2x) 1/2

expand

(2 y y^{'} (x) = 20 x^{3} - 2 x) \frac{1}{2}

yy' (x) = 20 x^{3} - x

Solution steps

(2 y y^{'} (x) = 20 x^{3} - 2 x) \frac{1}{2}

= \frac{1}{2} (2 \cdot 20 = x^{3} y y^{^{'}} (x) - 2 x)

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{1}{2}, b = 2 y y^{'} (x) = 20 x^{3}, c = 2 x

\frac{1}{2} \cdot 2 y y^{^{'}} (x) = 20 x^{3} - \frac{1}{2} \cdot 2 x

2 \cdot \frac{1}{2} y y^{^{'}} (x) = 20 x^{3} - 2 \cdot \frac{1}{2} x

Simplify

2 \cdot \frac{1}{2} y y^{'} (x) = 20 x^{3} - 2 \cdot \frac{1}{2} x : y y^{'} (x) = 20 x^{3} - x

y y^{'} (x) = 20 x^{3} - x

(x + 2 y = 1, 3) (x - 2 y = - 7)

- \frac{e ^{- 4 s}}{s ( s ^{2} + 2 s - 2 )}

\frac{2 X ^{2}}{( 0.04 - X ) \cdot ( 0.083 - X )}

(y + x y) d x + (2 y - x) d y

((ab + c d + e f + g h) + 1)^{2}

What is expand (2yy'(x)=20x^3-2x) 1/2 ?
The solution to expand (2yy'(x)=20x^3-2x) 1/2 is yy'(x)=20x^3-x