What is expand (4(6x^2-3))/((2x^3+3x)^2) ?

The solution to expand (4(6x^2-3))/((2x^3+3x)^2) is (24x^2-12)/(4x^6+12x^4+9x^2)

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expand (4(6x^2-3))/((2x^3+3x)^2)

expand

\frac{4 ( 6 x ^{2} - 3 )}{( 2 x ^{3} + 3 x ) ^{2}}

\frac{24 x ^{2} - 12}{4 x ^{6} + 12 x ^{4} + 9 x ^{2}}

Solution steps

\frac{4 ( 6 x ^{2} - 3 )}{( 2 x ^{3} + 3 x ) ^{2}}

(2 x^{3} + 3 x)^{2} = 4 x^{6} + 12 x^{4} + 9 x^{2}

= \frac{4 ( 6 x ^{2} - 3 )}{4 x ^{6} + 12 x ^{4} + 9 x ^{2}}

Expand

4 (6 x^{2} - 3) : 24 x^{2} - 12

= \frac{24 x ^{2} - 12}{4 x ^{6} + 12 x ^{4} + 9 x ^{2}}

(1 + x) d x

5 (1)^{2} + 8 (1) z - 44 (1) + 5 z^{2} - 46 z + 104

(1 - \frac{y}{x})^{2}

, (x - 1 r i g h t)

\frac{( - 5 s - 36 )}{( s + 2 ) ( s ^{2} + 9 )}

What is expand (4(6x^2-3))/((2x^3+3x)^2) ?
The solution to expand (4(6x^2-3))/((2x^3+3x)^2) is (24x^2-12)/(4x^6+12x^4+9x^2)