What is expand (7cos(θ)-3sin(θ))^2 ?

The solution to expand (7cos(θ)-3sin(θ))^2 is 49cos^2(θ)-42cos(θ)sin(θ)+9sin^2(θ)

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expand (7cos(θ)-3sin(θ))^2

expand

(7 cos (θ) - 3 sin (θ))^{2}

49 cos^{2} (θ) - 42 cos (θ) sin (θ) + 9 sin^{2} (θ)

Solution steps

(7 cos (θ) - 3 sin (θ))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(7 cos (θ) - 3 sin (θ))^{2} = (7 cos (θ))^{2} - 2 \cdot 7 cos (θ) \cdot 3 sin (θ) + (3 sin (θ))^{2}

= (7 cos (θ))^{2} - 2 \cdot 7 cos (θ) \cdot 3 sin (θ) + (3 sin (θ))^{2}

Simplify

(7 cos (θ))^{2} - 2 \cdot 7 cos (θ) \cdot 3 sin (θ) + (3 sin (θ))^{2} : 49 cos^{2} (θ) - 42 cos (θ) sin (θ) + 9 sin^{2} (θ)

= 49 cos^{2} (θ) - 42 cos (θ) sin (θ) + 9 sin^{2} (θ)

\frac{x ^{3} + x ^{2} - 3 x + 3}{( x + 4 ) ( x + 1 )}

\frac{4}{3} x^{2}

\frac{2 x + 32}{( x + 1 ) ( x + 7 )}

\frac{4}{3} x^{5}

\frac{d}{d t} ((x) (4 - 6 t^{2}))

What is expand (7cos(θ)-3sin(θ))^2 ?
The solution to expand (7cos(θ)-3sin(θ))^2 is 49cos^2(θ)-42cos(θ)sin(θ)+9sin^2(θ)