What is expand (x^2ln(x))/((x-1)^2) ?

The solution to expand (x^2ln(x))/((x-1)^2) is (x^2ln(x))/(x^2-2x+1)

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expand (x^2ln(x))/((x-1)^2)

expand

\frac{x ^{2} ln ( x )}{( x - 1 ) ^{2}}

\frac{x ^{2} ln ( x )}{x ^{2} - 2 x + 1}

Solution steps

\frac{x ^{2} ln ( x )}{( x - 1 ) ^{2}}

(x - 1)^{2} = x^{2} - 2 x + 1

= \frac{x ^{2} ln ( x )}{x ^{2} - 2 x + 1}

cos (2 (x + π))

π (25 x - x^{3})

\frac{1}{2} (ln (y + 2 x) + \frac{y}{y + 2 x}) + \frac{x ^{2}}{( 2 x + y ) ^{2}}

\frac{3 ( 401 - 1 )}{5}

\frac{x ^{3} - 1}{x ( 1 + x ^{3} )}

What is expand (x^2ln(x))/((x-1)^2) ?
The solution to expand (x^2ln(x))/((x-1)^2) is (x^2ln(x))/(x^2-2x+1)