What is expand (x^2+5/49)(x^2-4x+4) ?

The solution to expand (x^2+5/49)(x^2-4x+4) is x^4-4x^3+(201x^2)/(49)-(20x)/(49)+20/49

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expand (x^2+5/49)(x^2-4x+4)

expand

(x^{2} + \frac{5}{49}) (x^{2} - 4 x + 4)

x^{4} - 4 x^{3} + \frac{201 x ^{2}}{49} - \frac{20 x}{49} + \frac{20}{49}

Solution steps

(x^{2} + \frac{5}{49}) (x^{2} - 4 x + 4)

Distribute parentheses

= x^{2} x^{2} + x^{2} (- 4 x) + x^{2} \cdot 4 + \frac{5}{49} x^{2} + \frac{5}{49} (- 4 x) + \frac{5}{49} \cdot 4

Simplify

x^{2} x^{2} + x^{2} (- 4 x) + x^{2} \cdot 4 + \frac{5}{49} x^{2} + \frac{5}{49} (- 4 x) + \frac{5}{49} \cdot 4 : x^{4} - 4 x^{3} + \frac{201 x ^{2}}{49} - \frac{20 x}{49} + \frac{20}{49}

= x^{4} - 4 x^{3} + \frac{201 x ^{2}}{49} - \frac{20 x}{49} + \frac{20}{49}

- \frac{2 sec ^{2} ( x )}{( 1 + tan ( x ) ) ^{3}}

(v y - y) (v d y + y d v)

(3 a + 2) (3 a + 3)

\frac{4 !}{3 ! \cdot ( 1 - ( 1 - x ) ) ^{3} \cdot ( 1 - ( 1 - x ) ) ^{1}}

(\frac{1}{6} d - \frac{1}{3} q)^{2}

What is expand (x^2+5/49)(x^2-4x+4) ?
The solution to expand (x^2+5/49)(x^2-4x+4) is x^4-4x^3+(201x^2)/(49)-(20x)/(49)+20/49