What is (d^2}{d{x}d{y}}(({f}(x,y))(2{x}^2+3{y}^2-4{x)/y+2{y}-3)) ?

The answer to (d^2}{d{x}d{y}}(({f}(x,y))(2{x}^2+3{y}^2-4{x)/y+2{y}-3)) is {f}(x,y)(0+0-4+0-0)

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(d^2}{d{x}d{y}}(({f}(x,y))(2{x}^2+3{y}^2-4{x)/y+2{y}-3))

\frac{d ^{2}}{d x d y} ((f (x, y)) (2 x^{2} + 3 y^{2} - 4 x y + 2 y - 3))

f (x, y) (0 + 0 - 4 + 0 - 0)

Solution steps

\frac{d ^{2}}{d x d y} ((f (x, y)) (2 x^{2} + 3 y^{2} - 4 x y + 2 y - 3))

\frac{d}{d x} (f (x, y) (2 x^{2} + 3 y^{2} - 4 x y + 2 y - 3)) = f (x, y) (4 x + 0 - 4 y + 0 - 0)

= \frac{d}{d y} (f (x, y) (4 x + 0 - 4 y + 0 - 0))

\frac{d}{d y} (f (x, y) (4 x + 0 - 4 y + 0 - 0)) = f (x, y) (0 + 0 - 4 + 0 - 0)

= f (x, y) (0 + 0 - 4 + 0 - 0)

\frac{7 x - 3}{x ( x + 3 ) ( x - 1 )}

(4 + x) (5 + x)

(i w + 1)^{3}

\frac{( x + 6 ) ^{2}}{x + 8}

\frac{1}{( x + 1 ) ( x ^{2} + 1 ) ^{2}}

What is (d^2}{d{x}d{y}}(({f}(x,y))(2{x}^2+3{y}^2-4{x)/y+2{y}-3)) ?
The answer to (d^2}{d{x}d{y}}(({f}(x,y))(2{x}^2+3{y}^2-4{x)/y+2{y}-3)) is {f}(x,y)(0+0-4+0-0)