展开 e^{1+t}u(-t+2)

解答

展开

e^{1 + t} u (- t + 2)

- e^{1 + t} t u + 2 e^{1 + t} u

求解步骤

e^{1 + t} u (- t + 2)

使用分配律:

a (b + c) = ab + a c

a = e^{1 + t} u, b = - t, c = 2

= e^{1 + t} u (- t) + e^{1 + t} u \cdot 2

使用加减运算法则

+ (- a) = - a

= - e^{1 + t} t u + 2 e^{1 + t} u

e x p an d \frac{2 x ^{2} - 2 x - 4}{( 2 x - 1 ) ^{2}}

s im pl i f y \frac{3}{4} (x + \frac{1}{2} sin (2 x))

e x p an d \frac{( x ^{2} + 4 ) 3 x - 1 - x ^{2}}{x ^{2} + 4}

s im pl i f y f or (x^{4} + 20 - \frac{x ^{4}}{12})

e x p an d \frac{918 x ^{2} - 21 x - 124}{2 ( 6 x ^{2} - 5 x + 4 ) ( 9 x + 4 )}