What is expand (2(-3x+2))/(3x^3) ?

The solution to expand (2(-3x+2))/(3x^3) is -2/(x^2)+4/(3x^3)

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expand (2(-3x+2))/(3x^3)

expand

\frac{2 ( - 3 x + 2 )}{3 x ^{3}}

- \frac{2}{x ^{2}} + \frac{4}{3 x ^{3}}

Solution steps

\frac{2 ( - 3 x + 2 )}{3 x ^{3}}

Expand

2 (- 3 x + 2) : - 6 x + 4

= \frac{- 6 x + 4}{3 x ^{3}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 6 x + 4}{3 x ^{3}} = - \frac{6 x}{3 x ^{3}} + \frac{4}{3 x ^{3}}

= - \frac{6 x}{3 x ^{3}} + \frac{4}{3 x ^{3}}

Cancel

\frac{6 x}{3 x ^{3}} : \frac{2}{x ^{2}}

= - \frac{2}{x ^{2}} + \frac{4}{3 x ^{3}}

4 x^{2} - x (8 + 9 x^{4} - 5 x)

(y^{2} - 3 y - x) d y

\frac{4}{n} (\frac{n ( n + 1 )}{2})

- 15 (x cos (θ) - y sin (θ))

p (0, - 4) q (- 3, 0)

What is expand (2(-3x+2))/(3x^3) ?
The solution to expand (2(-3x+2))/(3x^3) is -2/(x^2)+4/(3x^3)