What is expand (27x^{4/3}+3(x^3+5))/(x^{2/3)} ?

The solution to expand (27x^{4/3}+3(x^3+5))/(x^{2/3)} is 27x^{2/3}+3x^{7/3}+(15)/(x^{2/3)}

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expand (27x^{4/3}+3(x^3+5))/(x^{2/3)}

expand

\frac{27 x ^{\frac{4}{3}} + 3 ( x ^{3} + 5 )}{x ^{\frac{2}{3}}}

27 x^{\frac{2}{3}} + 3 x^{\frac{7}{3}} + \frac{15}{x ^{\frac{2}{3}}}

Solution steps

\frac{27 x ^{\frac{4}{3}} + 3 ( x ^{3} + 5 )}{x ^{\frac{2}{3}}}

Expand

27 x^{\frac{4}{3}} + 3 (x^{3} + 5) : 27 x^{\frac{4}{3}} + 3 x^{3} + 15

= \frac{27 x ^{\frac{4}{3}} + 3 x ^{3} + 15}{x ^{\frac{2}{3}}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 x ^{\frac{4}{3}} + 3 x ^{3} + 15}{x ^{\frac{2}{3}}} = \frac{27 x ^{\frac{4}{3}}}{x ^{\frac{2}{3}}} + \frac{3 x ^{3}}{x ^{\frac{2}{3}}} + \frac{15}{x ^{\frac{2}{3}}}

= \frac{27 x ^{\frac{4}{3}}}{x ^{\frac{2}{3}}} + \frac{3 x ^{3}}{x ^{\frac{2}{3}}} + \frac{15}{x ^{\frac{2}{3}}}

Cancel

\frac{27 x ^{\frac{4}{3}}}{x ^{\frac{2}{3}}} : 27 x^{\frac{2}{3}}

= 27 x^{\frac{2}{3}} + \frac{3 x ^{3}}{x ^{\frac{2}{3}}} + \frac{15}{x ^{\frac{2}{3}}}

Cancel

\frac{3 x ^{3}}{x ^{\frac{2}{3}}} : 3 x^{\frac{7}{3}}

= 27 x^{\frac{2}{3}} + 3 x^{\frac{7}{3}} + \frac{15}{x ^{\frac{2}{3}}}

(a - 3 e)^{2}

(- 9 sin (t) + 9 sin (9 t))^{2}

e^{- t} + (- 1 - e^{- t}) U (t - 5)

4.408904562 \cdot 1 0^{36}

\frac{8 π ( 2 - 2 )}{3}

What is expand (27x^{4/3}+3(x^3+5))/(x^{2/3)} ?
The solution to expand (27x^{4/3}+3(x^3+5))/(x^{2/3)} is 27x^{2/3}+3x^{7/3}+(15)/(x^{2/3)}