展开 (m-5+sqrt(-3m^2+14m+5))^2

解答

展开

(m - 5 + - 3 m^{2} + 14 m + 5)^{2}

- 2 m^{2} - 10 - 3 m^{2} + 14 m + 5 + 4 m + 2 m - 3 m^{2} + 14 m + 5 + 30

求解步骤

(m - 5 + - 3 m^{2} + 14 m + 5)^{2}

使用指数法则:

a^{b + c} = a^{b} \cdot a^{c}

(m - 5 + - 3 m^{2} + 14 m + 5)^{2} = (m - 5 + - 3 m^{2} + 14 m + 5) (m - 5 + - 3 m^{2} + 14 m + 5)

= (m - 5 + - 3 m^{2} + 14 m + 5) (m - 5 + - 3 m^{2} + 14 m + 5)

打开括号

= mm + m (- 5) + m - 3 m^{2} + 14 m + 5 - 5 m - 5 (- 5) - 5 - 3 m^{2} + 14 m + 5 + - 3 m^{2} + 14 m + 5 m + - 3 m^{2} + 14 m + 5 (- 5) + - 3 m^{2} + 14 m + 5 - 3 m^{2} + 14 m + 5

化简

mm + m (- 5) + m - 3 m^{2} + 14 m + 5 - 5 m - 5 (- 5) - 5 - 3 m^{2} + 14 m + 5 + - 3 m^{2} + 14 m + 5 m + - 3 m^{2} + 14 m + 5 (- 5) + - 3 m^{2} + 14 m + 5 - 3 m^{2} + 14 m + 5 : - 2 m^{2} - 10 - 3 m^{2} + 14 m + 5 + 4 m + 2 m - 3 m^{2} + 14 m + 5 + 30

= - 2 m^{2} - 10 - 3 m^{2} + 14 m + 5 + 4 m + 2 m - 3 m^{2} + 14 m + 5 + 30

s im pl i f y 2 x (- 10 x - 6 + \frac{1}{x ^{3}})

e x p an d \frac{8}{s ( s - 2 ) ( s + 2 )}

e x p an d (a - L m) (c - ln (x)) - b^{2}

e x p an d \frac{8 + ( 8 + 16 cos ( x ) )}{2} (8 sin (x))

e x p an d \frac{e ^{- x}}{( x - 1 ) ( x - 2 ) ( x + 4 )}