展开 ,(2t^2-1)2dt

解答

展开

(2 t^{2} - 1) 2 d t

4 t^{2} d t - 2 d t

求解步骤

(2 t^{2} - 1) \cdot 2 d t

= 2 (2 t^{2} - 1) d t

使用分配律:

a (b - c) = ab - a c

a = 2 d t, b = 2 t^{2}, c = 1

= 2 d t \cdot 2 t^{2} - 2 d t \cdot 1

= 2 \cdot 2 t^{2} d t - 2 \cdot 1 \cdot d t

化简

2 \cdot 2 t^{2} d t - 2 \cdot 1 \cdot d t : 4 t^{2} d t - 2 d t

= 4 t^{2} d t - 2 d t

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